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06-27-2013,  02:30 PM #1

does anyone know how to write 16^-3/4 in radical notation? im stuck on this

06-27-2013,  02:40 PM #2

Originally Posted by claudette

does anyone know how to write 16^-3/4 in radical notation? im stuck on this

I'll do a different but similar problem for you:

$$(125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}$$

�... mathematics is only the art of saying the same thing in different words� - B. Russell

06-27-2013,  02:45 PM #3

Originally Posted by Subhotosh Khan I'll do a different but similar problem for you:

$$(125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}$$

i actually figured that part out now im trying to figure out how to evaluate the expression now

06-27-2013,  02:47 PM #4

Originally Posted by claudette

i actually figured that part out now im trying to figure out how to evaluate the expression now

Okay ... go at it ... show your work if you need help.

�... mathematics is only the art of saying the same thing in different

words� - B. Russell

06-27-2013,  04:37 PM #5

If you consider the factors of 16, the fourthrootshould be clear.
Last edited by HallsofIvy; 06-27-2013 at04:40 PM .

06-27-2013,  04:42 PM #6

Originally Posted by HallsofIvy

If you give the factors of 125 some thought, the cuberootshould be clear.

Her problem is to evaluate $$\displaystyle \left [16\right ]^{\frac{-3}{4}}$$.

The problem with 125 was made up by me.

�... mathematics is only the art of saying the same thing in different words� - B. Russell

06-27-2013,  07:47 PM #7

Oh hi Claudette: am I still your favorite?

I'm just an imagination of your figment !

06-28-2013,  01:35 PM #8

Originally Posted by claudette

does anyone know how to write 16^-3/4 in radical notation? im stuck on this

Claudette, you must use grouping symbols, such as in "16^(-3/4)." Also, for appropriate numbers, as in this case, the expression is equivalent to: $$\ \ \dfrac{1}{(\sqrt[4]{16})^3}$$ $$\ \ \ \ \ Continue \ \ with \ \ that.$$

Category: Writing