# Thread: radical notation

06-27-2013, 02:30 PM #1

does anyone know how to write 16^-3/4 in radical notation? im stuck on this

06-27-2013, 02:40 PM #2

Originally Posted byclaudettedoes anyone know how to write 16^-3/4 in radical notation? im stuck on this

I'll do a different but similar problem for you:[tex] (125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}[/tex]

�... mathematics is only the art of saying the same thing in different words� - B. Russell

06-27-2013, 02:45 PM #3

Originally Posted bySubhotosh KhanI'll do a different but similar problem for you:[tex] (125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}[/tex]

i actually figured that part out now im trying to figure out how to evaluate the expression now

06-27-2013, 02:47 PM #4

Originally Posted byclaudettei actually figured that part out now im trying to figure out how to evaluate the expression now

Okay ... go at it ... show your work if you need help.

�... mathematics is only the art of saying the same thing in different

words� - B. Russell

06-27-2013, 04:37 PM #5

If you consider the factors of 16, the fourthrootshould be clear.

Last edited by HallsofIvy; 06-27-2013 at04:40 PM .

06-27-2013, 04:42 PM #6

Originally Posted byHallsofIvyIf you give the factors of 125 some thought, the cuberootshould be clear.

Her problem is to evaluate [tex]\displaystyle \left [16\right ]^{\frac{-3}{4}}[/tex].The problem with 125 was made up by me.

�... mathematics is only the art of saying the same thing in different words� - B. Russell

06-27-2013, 07:47 PM #7

Oh hi Claudette: am I still your favorite?

I'm just an imagination of your figment !

06-28-2013, 01:35 PM #8

Originally Posted byclaudettedoes anyone know how to write 16^-3/4 in radical notation? im stuck on this

Claudette, you must use grouping symbols, such as in "16^(-3/4)." Also, for appropriate numbers, as in this case, the expression is equivalent to: [tex] \ \ \dfrac{1}{(\sqrt[4]{16})^3} [/tex] [tex] \ \ \ \ \ Continue \ \ with \ \ that.[/tex]

Category: Writing