Thread: radical notation

    06-27-2013,  02:30 PM #1

    does anyone know how to write 16^-3/4 in radical notation? im stuck on this

    06-27-2013,  02:40 PM #2

    Originally Posted by claudette

    does anyone know how to write 16^-3/4 in radical notation? im stuck on this

    I'll do a different but similar problem for you:

    [tex] (125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}[/tex]

    �... mathematics is only the art of saying the same thing in different words� - B. Russell

    06-27-2013,  02:45 PM #3

    Originally Posted by Subhotosh Khan I'll do a different but similar problem for you:

    [tex] (125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}[/tex]

    i actually figured that part out now im trying to figure out how to evaluate the expression now

    06-27-2013,  02:47 PM #4

    Originally Posted by claudette

    i actually figured that part out now im trying to figure out how to evaluate the expression now

    Okay ... go at it ... show your work if you need help.

    �... mathematics is only the art of saying the same thing in different

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    words� - B. Russell

    06-27-2013,  04:37 PM #5

    If you consider the factors of 16, the fourthrootshould be clear.
    Last edited by HallsofIvy; 06-27-2013 at04:40 PM .

    06-27-2013,  04:42 PM #6

    Originally Posted by HallsofIvy

    If you give the factors of 125 some thought, the cuberootshould be clear.

    Her problem is to evaluate [tex]\displaystyle \left [16\right ]^{\frac{-3}{4}}[/tex].

    The problem with 125 was made up by me.

    �... mathematics is only the art of saying the same thing in different words� - B. Russell

    06-27-2013,  07:47 PM #7

    Oh hi Claudette: am I still your favorite?

    I'm just an imagination of your figment !

    06-28-2013,  01:35 PM #8

    Originally Posted by claudette

    does anyone know how to write 16^-3/4 in radical notation? im stuck on this

    Claudette, you must use grouping symbols, such as in "16^(-3/4)." Also, for appropriate numbers, as in this case, the expression is equivalent to: [tex] \ \ \dfrac{1}{(\sqrt[4]{16})^3} [/tex] [tex] \ \ \ \ \ Continue \ \ with \ \ that.[/tex]


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